Trigonometrical Equations
easy

If $\sin 2\theta = \cos 3\theta $ and $\theta $ is an acute angle, then $\sin \theta $ is equal to

A

$\frac{{\sqrt 5 - 1}}{4}$

B

$\frac{{ - \sqrt 5 - 1}}{4}$

C

$0$

D

None of these

Solution

(a) $\sin 2\theta = \cos 3\theta $

$ \Rightarrow $ $3\theta = 2n\pi \pm \left( {\frac{\pi }{2} – 2\theta } \right)$

$ \Rightarrow $ $\theta = \frac{{2n\pi }}{5} + \frac{\pi }{{10}}$

or $\theta = 2n\pi – \frac{\pi }{2}$.

Since $\theta $ is acute

==> $\theta = \frac{\pi }{{10}}$

==> $\sin \theta = \frac{{\sqrt 5 – 1}}{4}$.

Standard 11
Mathematics

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