If sin 2theta = cos 3theta and theta is an | vedclass

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Question

(a) $\sin 2	heta = \cos 3	heta $

$ \Rightarrow $ $3	heta = 2n\pi \pm \left( {\frac{\pi }{2} - 2	heta } ight)$

$ \Rightarrow $ $	heta = \f

Vedclass · Accepted Answer

$\frac{{\sqrt 5 - 1}}{4}$

Vedclass · Answer

(a) $\sin 2	heta = \cos 3	heta $

$ \Rightarrow $ $3	heta = 2n\pi \pm \left( {\frac{\pi }{2} - 2	heta } ight)$

$ \Rightarrow $ $	heta = \frac{{2n\pi }}{5} + \frac{\pi }{{10}}$

or $	heta = 2n\pi - \frac{\pi }{2}$.

Since $	heta $ is acute

==> $	heta = \frac{\pi }{{10}}$

==> $\sin 	heta = \frac{{\sqrt 5 - 1}}{4}$.

If $\sin 2\theta = \cos 3\theta $ and $\theta $ is an acute angle, then $\sin \theta $ is equal to

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