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Trigonometrical Equations
normal
જો $\tan \theta = - \frac{1}{{\sqrt 3 }}$ અને $\sin \theta = \frac{1}{2}$, $\cos \theta = - \frac{{\sqrt 3 }}{2}$, તો $\theta $ ની કિમત મેળવો.
A
$\frac{\pi }{6}$
B
$\frac{{5\pi }}{6}$
C
$\frac{{7\pi }}{6}$
D
$ - \frac{\pi }{6}$
Solution
(b) $\tan \theta = \frac{{ – 1}}{{\sqrt 3 }} = \tan \left( {\pi – \frac{\pi }{6}} \right)$,
$\sin \theta = \frac{1}{2} = \sin \left( {\pi – \frac{\pi }{6}} \right)$
and $\cos \theta = \frac{{ – \sqrt 3 }}{2}$= $\cos \left( {\pi – \frac{\pi }{6}} \right)$
Hence principal value is $\theta = \frac{{5\pi }}{6}$.
Standard 11
Mathematics
