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10-2. Parabola, Ellipse, Hyperbola
easy
If $y = mx + c$ is tangent on the ellipse $\frac{{{x^2}}}{9} + \frac{{{y^2}}}{4} = 1$, then the value of $c$ is
A
$0$
B
$3/m$
C
$ \pm \sqrt {9{m^2} + 4} $
D
$ \pm 3\sqrt {1 + {m^2}} $
Solution
(c) Here, $a = 3,\,\,b = 2$.
By formula, ${c^2} = {b^2} + {a^2}{m^2}$
${c^2} = 4 + 9{m^2}$; $c = \pm \sqrt {9{m^2} + 4} $.
Standard 11
Mathematics