13.Nuclei
medium

यदि $ {N_0} $ किसी पदार्थ का मूल द्रव्यमान है एवं इसका अर्द्धआयुकाल ${T_{1/2}} = 5$ वर्ष है। तो $15$ वर्षो बाद बचे पदार्थ की मात्रा है

A

${N_0}/8$

B

${N_0}/16$

C

${N_0}/2$

D

${N_0}/4$

(AIEEE-2002)

Solution

(a) $N = {N_0}{\left( {\frac{1}{2}} \right)^{\frac{t}{{{T_{1/2}}}}}} $

.$= {N_0}{\left( {\frac{1}{2}} \right)^{\frac{{15}}{5}}} = \frac{{{N_0}}}{8}$

Standard 12
Physics

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