4-2.Quadratic Equations and Inequations
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જો $\alpha ,\beta ,\gamma$ એ સમીકરણ $x^3 - x - 2 = 0$ ના બીજો હોય તો $\alpha^5 + \beta^5 + \gamma^5$ ની કિમત મેળવો 

A

$5$

B

$8$

C

$9$

D

$10$

Solution

$\alpha \,is\,a\,root\, \Rightarrow \,{\alpha ^3} = \,\alpha  + 2 $  $  \Rightarrow {\alpha ^5} = {\alpha ^3} + 2{\alpha ^2} = \alpha  + 2 + 2{\alpha ^2} $ $  \therefore {\alpha ^5} + {\beta ^5} + {\gamma ^5} = 2({\alpha ^2} + {\beta ^2} + {\gamma ^2}) + ({\alpha ^{}} + \beta  + \gamma ) + 6 $ $   = 2(\sum \alpha  – 2\sum \alpha \beta ) + \sum \alpha  + 6$ $   = 2(0 – 2( – 1)) + 0 + 6 = 10 $

Standard 11
Mathematics

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