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8. Sequences and Series
normal
જો $x = \,\frac{4}{3}\, - \,\frac{{4x}}{9}\, + \,\,\frac{{4{x^2}}}{{27}}\, - \,\,.....\,\infty $ , હોય તો $x$ ની કિમત મેળવો
A
માત્ર $1$
B
$1$ અથવા $-4$
C
માત્ર $-4$
D
$-1$ અથવા $4$
Solution
$\Rightarrow x=\frac{4}{3}\left(\frac{1}{1+\frac{x}{3}}\right)=\frac{4}{3+x}$
$\Rightarrow 3 x+x^{2}=4$
$\Rightarrow x^{2}+3 x-4 \Rightarrow(x+4)(x-1)=0$
$\Rightarrow x=1,-4$
$\Rightarrow x=1$ only as $\left|-\frac{4}{3}\right|>1$
Standard 11
Mathematics
