- Home
- Standard 11
- Mathematics
13.Statistics
hard
If the mean of the frequency distribution
Class: | $0-10$ | $10-20$ | $20-30$ | $30-40$ | $40-50$ |
Frequency | $2$ | $3$ | $x$ | $5$ | $4$ |
is $28$ , then its variance is $........$.
A
$150$
B
$152$
C
$153$
D
$151$
(JEE MAIN-2023)
Solution
Given mean is $=28$
$\frac{2 \times 5+3 \times 15+x \times 25+5 \times 35+4 \times 45}{14+x}=28$
$x =6$
$\text { Variance }=\left(\frac{\sum x_i^2 f_i}{\sum f_i}\right)-(\text { mean })^2$
$\text { Variance }==\frac{2 \times 5^2+3 \times 15^2+6 \times 25^2+5 \times 35^2+4 \times 45^2}{20}-(28)^2$
$=151$
Standard 11
Mathematics
Similar Questions
The diameters of circles (in mm) drawn in a design are given below:
Diameters | $33-36$ | $37-40$ | $41-44$ | $45-48$ | $49-52$ |
No. of circles | $15$ | $17$ | $21$ | $22$ | $25$ |
Calculate the standard deviation and mean diameter of the circles.
[ Hint : First make the data continuous by making the classes as $32.5-36.5,36.5-40.5,$ $40.5-44.5,44.5-48.5,48.5-52.5 $ and then proceed.]
medium