$\left[ {{{\left( {1 + x} \right)}^{100}} + {{\left( {1 + {x^2}} \right)}^{100}}{{\left( {1 + {x^3}} \right)}^{100}}} \right]$  ના વિસ્તરણમાં કુલ કેટલા પદો હોય ?

જો ${(1 + x)^n} = {C_0} + {C_1}x + {C_2}{x^2} + ………. + {C_n}{x^n}$, તો $\frac{{{C_1}}}{{{C_0}}} + \frac{{2{C_2}}}{{{C_1}}} + \frac{{3{C_3}}}{{{C_2}}} + …. + \frac{{n{C_n}}}{{{C_{n – 1}}}} = $

$\left( {\left( {\begin{array}{*{20}{c}}
{21}\\
1
\end{array}} \right) – \left( {\begin{array}{*{20}{c}}
{10}\\
1
\end{array}} \right)} \right) + \left( {\left( {\begin{array}{*{20}{c}}
{21}\\
2
\end{array}} \right) – \left( {\begin{array}{*{20}{c}}
{10}\\
2
\end{array}} \right)} \right)$$ + \left( {\left( {\begin{array}{*{20}{c}}
{21}\\
3
\end{array}} \right) – \left( {\begin{array}{*{20}{c}}
{10}\\
3
\end{array}} \right)} \right) + \;.\;.\;.$$ + \left( {\left( {\begin{array}{*{20}{c}}
{21}\\
{10}
\end{array}} \right) – \left( {\begin{array}{*{20}{c}}
{10}\\
{10}
\end{array}} \right)} \right) = $

$\frac{1}{{1!(n – 1)\,!}} + \frac{1}{{3!(n – 3)!}} + \frac{1}{{5!(n – 5)!}} + …. = $

જો ${s_1} = \mathop \sum \limits_{j = 1}^{10} j\left( {j – 1} \right)\left( {\begin{array}{*{20}{c}}{10}\\j\end{array}} \right)\;,$$\;{s_2} = \mathop \sum \limits_{j = 1}^{10} j\;\left( {\begin{array}{*{20}{c}}{10}\\j\end{array}} \right)\;and,$${s_3} = \mathop \sum \limits_{j = 1}^{10} {j^2}\left( {\begin{array}{*{20}{c}}{10}\\j\end{array}} \right)\;,\;$

વિધાન $1$:${s_3} = 55 \times {2^9}$

વિધાન $2$: ${s_1} = 90 \times {2^8}\;$અને ${s_2} = 10 \times {2^8}$