3 and 4 .Determinants and Matrices
medium

यदि समीकरण निकाय $3x - 2y + z = 0$, $\lambda x - 14y + 15z = 0$, $x + 2y + 3z = 0$ अशून्य हल रखता है, तब $\lambda  = $

A

$5$

B

$-5$

C

$-29$

D

$29$

Solution

यदि दिए गये समीकरणों का निकाय अशून्य हल रखता है,  तब $\left| {\,\begin{array}{*{20}{c}}3&{ – 2}&1\\\lambda &{ – 14}&{15}\\1&2&3\end{array}\,} \right| = 0 \Rightarrow \lambda  = 29$.

Standard 12
Mathematics

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