In a triangle tan A + tan B + tan C = 6 and t | vedclass

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(c) $	an A + 	an B + 	an C = 	an A	an B	an C$ 

$	herefore 	an A	an B	an C = 6 \Rightarrow 	an C = \frac{6}{2} = 3$ 

Also $\

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$(a)$ and $(b)$ both

Vedclass · Answer

(c) $	an A + 	an B + 	an C = 	an A	an B	an C$ 

$	herefore 	an A	an B	an C = 6 \Rightarrow 	an C = \frac{6}{2} = 3$ 

Also $	an A + 	an B = 6 - 3 = 3$ 

$	herefore 	an A,	an B = 2,1$ or $1, 2$ and $	an C = 3$.

In a triangle $\tan A + \tan B + \tan C = 6$ and $\tan A\tan B = 2,$ then the values of $\tan A,\,\,\tan B$ and $\tan C$ are

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