In the mean value theorem, $f(b) - f(a) = (b - a)f'(c)$if $a = 4$, $b = 9$ and $f(x) = \sqrt x $ then the value of $c$ is
In the mean value theorem, $f(b) - f(a) = (b - a)f'(c)$if $a = 4$, $b = 9$ and $f(x) = \sqrt x $ then the value of $c$ is
- A
$1 - {{\sqrt {15} } \over 6}$
- B
$1 + \sqrt {15} $
- C
$1 - {{\sqrt {21} } \over 6}$
- D
$1 + \sqrt {21} $
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