It is easy to see that f is one-one and onto, so that f is invertible with inverse f^{-1} of f given

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1.Relation and Function

easy

It is easy to see that $f$ is one-one and onto, so that $f$ is invertible with the inverse $f^{-1}$ of $f$ given by $f^{-1}=\{(1,2),(2,1),(3,1)\}=f$

Option A

Option B

Option C

Option D

Solution

since $f(2)=f(3)=1, f$ is not one-one, so that $f$ is not invertible.

Standard 12

Mathematics

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