Gujarati
1.Relation and Function
normal

Let $R$ be the set of real numbers and $f: R \rightarrow R$ be defined by $f(x)=\frac{\{x\}}{1+[x]^2}$, where $[x]$ is the greatest integer less than or equal to $x$, and $\left\{x{\}}=x-[x]\right.$. Which of the following statements are true?

$I.$ The range of $f$ is a closed interval.

$II.$ $f$ is continuous on $R$.

$III.$ $f$ is one-one on $R$

A

$I$ only

B

$II$ only

C

$III$ only

D

None of $I$,$II$ and $III$

(KVPY-2017)

Solution

(d)

We have,

$f(x) =\frac{\{x\}}{1+[x]^2}$

$\Rightarrow \quad f(x) =\frac{x-[x]}{1+[x]^2}$

Range of $f(x)=[0,1)$.

$\therefore$ Range of $f$ is semi-closed interval $f$ is discontinuous on integer.

Clearly, $f$ is not one-one function.

$\therefore$ Option $(d)$ is correct.

Standard 12
Mathematics

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