9.Straight Line
medium

किसी आयत की एक भुजा $4x + 7y + 5 = 0$ के अनुदिश है। इसके दो शीर्ष $(-3, 1)$ व $(1, 1)$ हैं, तो अन्य तीन भुजाओं के समीकरण हैं

A

$7x - 4y + 25 = 0,$$4x + 7y = 11$ व $7x - 4y - 3 = 0$

B

$7x + 4y + 25 = 0,$$7y + 4x - 11 = 0$ व $7x - 4y - 3 = 0$

C

$4x - 7y + 25 = 0,$$7x + 4y - 11 = 0$ व $4x - 7y - 3 = 0$

D

इनमें से कोई नहीं

(IIT-1978)

Solution

(a) (i) $4x + 7y = 4( – 3) + 7 = – 5$
(ii) $7x – 4y = 7( – 3) – 4 = – 25$
(iii) $4x + 7y = 4(1) + 7(1) = 11$
(iv) $7x – 4y = 7(1) – 4(1) = 3$

Standard 11
Mathematics

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