Prove the following identities, where the angles involved are acute angles for which the expressions are defined.
$(\sin A+\operatorname{cosec} A)^{2}+(\cos A+\sec A)^{2}=7+\tan ^{2} A+\cot ^{2} A$
$(\sin A+\operatorname{cosec} A)^{2}+(\cos A+\sec A)^{2}=7+\tan ^{2} A+\cot ^{2} A$
$L.H.S.=(\sin A+\operatorname{cosec} A)^{2}+(\cos A+\sec A)^{2}$
$\quad=\sin ^{2} A+\operatorname{cosec}^{2} A+2 \sin A \operatorname{cosec} A+\cos ^{2} A+\sec ^{2} A+2 \cos A \sec A$
$\quad=\left(\sin ^{2} A+\cos ^{2} A\right)+\left(\operatorname{cosec}^{2} A+\sec ^{2} A\right)+2 \sin A\left(\frac{1}{\sin A}\right)+2 \cos A\left(\frac{1}{\cos A}\right)$
$\quad=(1)+\left(1+\cot ^{2} A+1+\tan ^{2} A\right)+(2)+(2)$
$\quad=7+\tan ^{2} A+\cot ^{2} A$
$=R \cdot H . S.$
Evaluate the following:
$2 \tan ^{2} 45^{\circ}+\cos ^{2} 30^{\circ}-\sin ^{2} 60^{\circ}$
Prove that $\frac{\cot A-\cos A}{\cot A+\cos A}=\frac{\operatorname{cosec} A-1}{\operatorname{cosec} A+1}$
Evaluate the following:
$\frac{5 \cos ^{2} 60^{\circ}+4 \sec ^{2} 30^{\circ}-\tan ^{2} 45^{\circ}}{\sin ^{2} 30^{\circ}+\cos ^{2} 30^{\circ}}$
In $\triangle$ $OPQ$, right-angled at $P$, $OP =7\, cm$ and $OQ - PQ =1\, cm$ (see $Fig.$). Determine the values of $\sin Q$ and $\cos Q$.
Evaluate the following:
$\frac{\cos 45^{\circ}}{\sec 30^{\circ}+\operatorname{cosec} 30^{\circ}}$