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4-1.Complex numbers
easy
$\frac{{1 + \sqrt 3 \,i}}{{\sqrt 3 - i}}$ का कोणांक है
A
$0$
B
$\pi /6$
C
$\pi /3$
D
$\pi /2$
Solution
(d)$z = \frac{{1 + \sqrt 3 i}}{{\sqrt 3 – i}}$$ = \,\frac{{1 + \sqrt 3 i}}{{\sqrt 3 – i}} \times $$\frac{{\sqrt 3 + i}}{{\sqrt 3 + i}}$
$ = \frac{{\sqrt 3 + i + 3i – \sqrt 3 }}{{3 + 1}}$=$\frac{{4i}}{4} = i$
$amp\ (z) = \,\pi /2$ $[\because \,\tan \theta = b/a]$
Standard 11
Mathematics