Gujarati
10-2. Parabola, Ellipse, Hyperbola
medium

The centre of the ellipse$\frac{{{{(x + y - 2)}^2}}}{9} + \frac{{{{(x - y)}^2}}}{{16}} = 1$ is

A

$(0, 0)$

B

$(1, 1)$

C

$(1, 0)$

D

$(0, 1)$

Solution

(b) The centre of the given ellipse is the point of intersection of the lines $x + y – 2 = 0$ and $x – y = 0$  $i.e.$,$(1,1).$

Standard 11
Mathematics

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