The converse of the statement $((\sim p) \wedge q) \Rightarrow r$ is

  • [JEE MAIN 2023]
  • A

    $(\sim r ) \Rightarrow p \wedge q$

  • B

    $(\sim r ) \Rightarrow((\sim p ) \wedge q )$

  • C

    $((\sim p) \vee q) \Rightarrow r$

  • D

    $( p \vee(\sim q )) \Rightarrow(\sim r )$

Similar Questions

The maximum number of compound propositions, out of $p \vee r \vee s , p \vee P \vee \sim s , p \vee \sim q \vee s$,

$\sim p \vee \sim r \vee s , \sim p \vee \sim r \vee \sim s , \sim p \vee q \vee \sim s$, $q \vee r \vee \sim s , q \vee \sim r \vee \sim s , \sim p \vee \sim q \vee \sim s$

that can be made simultaneously true by an assignment of the truth values to $p , q , r$ and $s$, is equal to

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The Boolean expression $ \sim \left( {p \Rightarrow \left( { \sim q} \right)} \right)$ is equivalent to

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The statement $\sim(p\leftrightarrow \sim q)$ is :

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