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Trigonometrical Equations
easy
સમીરકણ $\sin x + \cos x = 2$ ના બીજની સંખ્યા . . . . છે.
A
$1$
B
$2$
C
અનંત
D
એકપણ ઉકેલ શક્ય નથી
Solution
(d) No solution as $|\sin x| \le 1,\,|\cos x| \le 1$ and both of them do not attain their maximum value for the same angle.
Aliter : Since the maximum value of $(\sin x + \cos x) = \sqrt {{1^2} + {1^2}} = \sqrt 2 $.
Hence there is no satisfying $\sin x + \cos x = 2$.
Standard 11
Mathematics
