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13.Nuclei
hard
The half-life of $Au ^{198}$ is $2.7\, days.$ The activity of $1.50\, mg$ of $Au ^{198}$ if its atomic weight is $198\, g mol ^{-1}$ is .......$Ci$ $\left( N _{ A }=6 \times 10^{23}\, / mol \right)$
A
$240$
B
$357$
C
$535$
D
$252$
(JEE MAIN-2021)
Solution
$A =\lambda N$
$N = nN _{ A }$$\quad\left( t _{1 / 2}=\frac{\ln 2}{\lambda}\right)$
$N =\left(\frac{1.5 \times 10^{-3}}{198}\right) N _{ A }$
$A=\left(\frac{\ln 2}{t_{1 / 2}}\right) N$
$1$ Curie $=3.7 \times 10^{10}\, Bq$
$A =365\, Bq$
Standard 12
Physics