13.Nuclei
hard

The half-life of $Au ^{198}$ is $2.7\, days.$ The activity of $1.50\, mg$ of $Au ^{198}$ if its atomic weight is $198\, g mol ^{-1}$ is .......$Ci$ $\left( N _{ A }=6 \times 10^{23}\, / mol \right)$

A

$240$

B

$357$

C

$535$

D

$252$

(JEE MAIN-2021)

Solution

$A =\lambda N$

$N = nN _{ A }$$\quad\left( t _{1 / 2}=\frac{\ln 2}{\lambda}\right)$

$N =\left(\frac{1.5 \times 10^{-3}}{198}\right) N _{ A }$

$A=\left(\frac{\ln 2}{t_{1 / 2}}\right) N$

$1$ Curie $=3.7 \times 10^{10}\, Bq$

$A =365\, Bq$

Standard 12
Physics

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