The number of values of x for which sin2x + s | vedclass

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Question

$\sin 2 x+\sin 4 x=2$

$\sin 2 x=1, \sin 4 x=1$

$2 \mathrm{x}=\mathrm{n} \pi+(-1)^{\mathrm{n}} \frac{\pi}{2}, 4 \mathrm{x}=\mathrm{m} \pi+(-1)^{\

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Vedclass · Answer

$\sin 2 x+\sin 4 x=2$

$\sin 2 x=1, \sin 4 x=1$

$2 \mathrm{x}=\mathrm{n} \pi+(-1)^{\mathrm{n}} \frac{\pi}{2}, 4 \mathrm{x}=\mathrm{m} \pi+(-1)^{\mathrm{m}} \frac{\pi}{2}$

$x=\frac{n \pi}{2}+(-1)^{n} \frac{\pi}{4}, \quad x=\frac{m \pi}{4}+(-1)^{m} \frac{\pi}{8}$

The number of values of $x$ for which $sin2x + sin4x = 2$ is

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