The statement $( p \wedge q ) \Rightarrow( p \wedge r )$ is equivalent to.
$q \Rightarrow(p \wedge r)$
$p \Rightarrow( p \wedge r )$
$( p \wedge r ) \Rightarrow( p \wedge q )$
$(p \wedge q) \Rightarrow r$
The negation of the statement $q \wedge \left( { \sim p \vee \sim r} \right)$
The maximum number of compound propositions, out of $p \vee r \vee s , p \vee P \vee \sim s , p \vee \sim q \vee s$,
$\sim p \vee \sim r \vee s , \sim p \vee \sim r \vee \sim s , \sim p \vee q \vee \sim s$, $q \vee r \vee \sim s , q \vee \sim r \vee \sim s , \sim p \vee \sim q \vee \sim s$
that can be made simultaneously true by an assignment of the truth values to $p , q , r$ and $s$, is equal to
If $p$ : It rains today, $q$ : I go to school, $r$ : I shall meet any friends and $s$ : I shall go for a movie, then which of the following is the proposition : If it does not rain or if I do not go to school, then I shall meet my friend and go for a movie.
Which statement given below is tautology ?