Gujarati
8. Sequences and Series
medium

श्रेणी $.9 + .09 + .009.........$ के $100$ पदों का योग होगा

A

$1 - {\left( {\frac{1}{{10}}} \right)^{100}}$

B

$1 + {\left( {\frac{1}{{10}}} \right)^{100}}$

C

$1 - {\left( {\frac{1}{{10}}} \right)^{106}}$

D

$1 + {\left( {\frac{1}{{10}}} \right)^{106}}$

Solution

(a) दी गयी श्रेणी गुणोत्तर श्रेणी है, जहाँ $a = 0.9 = \frac{9}{{10}}$ एवं $r = \frac{1}{{10}} = 0.1$

$\therefore $${S_{100}} = a\left( {\frac{{1 – {r^{100}}}}{{1 – r}}}\right) = \frac{9}{{10}}\left( {\frac{{1 – \frac{1}{{{{10}^{100}}}}}}{{1 – \frac{1}{{10}}}}} \right) = 1 – \frac{1}{{{{10}^{100}}}}$. 

Standard 11
Mathematics

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