7.Binomial Theorem
easy

${({x^2} + x - 3)^{319}}$ के प्रसार में सभी गुणांकों का योग है

A

$1$

B

$2$

C

$-1$

D

$0$

Solution

${({x^2} + x – 3)^{319}}$ में $x = 1$ रखने पर,

गुणांकों का योग = ${(1 + 1 – 3)^{319}}$ $= -1$

Standard 11
Mathematics

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