7.Binomial Theorem
medium

જો ${[x + {x^{{{\log }_{10}}}}^{(x)}]^5}$ ના વિસ્તરણમાં ત્રીજું પદ $10,00,000$ હોય તો $x$ મેળવો.

A

$10$

B

$11$

C

$12$

D

એકપણ નહીં.

Solution

(a) ${T_3} = {\,^5}{C_2}.{x^2}{({x^{{{\log }_{10}}x}})^3} = {10^6}$

Put . $^5{C_2} = 10\,\,\,\,\,[{\log _{10}}10 = 1]$

If $x = 10$, then ${10^3}{.10^{2.1}} = {10^5}$ is satisfied.

Hence $ x =10.$

Standard 11
Mathematics

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