$\left| {\,\begin{array}{*{20}{c}}1&{\cos (\alpha - \beta )}&{\cos \alpha }\\{\cos (\alpha - \beta )}&1&{\cos \beta }\\{\cos \alpha }&{\cos \beta }&1\end{array}\,} \right|=$

  • A

    ${\alpha ^2} + {\beta ^2}$

  • B

    ${\alpha ^2} - {\beta ^2}$

  • C

    $1$

  • D

    $0$

Similar Questions

$\left| {\,\begin{array}{*{20}{c}}1&a&{{a^2} - bc}\\1&b&{{b^2} - ac}\\1&c&{{c^2} - ab}\end{array}\,} \right| = $

  • [IIT 1988]

$\left| {\,\begin{array}{*{20}{c}}{{{\sin }^2}x}&{{{\cos }^2}x}&1\\{{{\cos }^2}x}&{{{\sin }^2}x}&1\\{ - 10}&{12}&2\end{array}\,} \right| = $

જો $[.]$ , $ \{.\} $ અને $sgn$$(.)$ અનુક્રમે  મહતમ પૃણાંક , પૃણાંક વિધેય, અને ચિન્હ વિધેય છે તો

$\left| {\begin{array}{*{20}{c}}
  {\left[ \pi  \right]}&{amp(1 + i\sqrt 3 )}&1 \\ 
  1&0&2 \\ 
  {\operatorname{sgn} ({{\cot }^{ - 1}}x)}&1&{\{ \pi \} } 
\end{array}} \right|$ ની કિમંત મેળવો.

$\Delta ABC$ માં , જો $\left| {\,\begin{array}{*{20}{c}}1&a&b\\1&c&a\\1&b&c\end{array}\,} \right| = 0$, તો ${\sin ^2}A + {\sin ^2}B + {\sin ^2}C = $

$\Delta=\left|\begin{array}{lll}3 & 2 & 3 \\ 2 & 2 & 3 \\ 3 & 2 & 3\end{array}\right|$ નું મૂલ્ય શોધો. ( ${R_1} = {R_3}$ છે. )