13.Statistics
medium

પ્રથમ $50 $ યુગ્મ પ્રાકૃતિક સંખ્યાઓનું વિચરણ .. . . . . .છે.

A

$437$

B

$\frac{{437}}{4}$

C

$\frac{{833}}{4}$

D

$833$

(JEE MAIN-2014)

Solution

$2,4,6,8,……,98,100$

${\sigma ^2} = \frac{{\sum x_1^2}}{n} – {\left( {\overline {.x} } \right)^2}$

$\frac{{{2^2} + {4^2} + {6^2} + …. + {{100}^2}}}{{50}}$$ – {\left( {\frac{{2 + 4 + 6 + …. + 100}}{{50}}} \right)^2}$

${i_1} = \frac{{{2^2} + {4^2} + {6^2} + …. + {{100}^2}}}{{50}}$

$ = {2^2}\frac{{{1^2} + {2^2} + {3^2} + … + {{50}^2}}}{{50}}$

$ = \frac{{{2^2}}}{{50}} \times 50\left( {50 + 1} \right)\left( {100 + 1} \right)$

$ = 3434$

${i_2} = {\left( {\frac{{2 + 4 + 6 + ….. + 100}}{{50}}} \right)^2}$

$ = {\left( {\frac{{50 \times \frac{{2 + 100}}{2}}}{{50}}} \right)^2}$

$ = {\left( {51} \right)^2}$

${\sigma ^2} = 3434 – 2661 = 833$

Standard 11
Mathematics

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