8. Sequences and Series
easy

अनुक्रम में प्रत्येक के प्रथम पाँच पद लिखिये, जिनका $n$ वाँ पद दिया गया है

$a_{n}=n(n+2)$

A

$3,8,15,24,35$

B

$3,8,15,24,35$

C

$3,8,15,24,35$

D

$3,8,15,24,35$

Solution

$a_{n}=n(n+2)$

Substituting $n=1,2,3,4$ and $5,$ we obtain

$a_{1}=1(1+2)=3$

$a_{2}=2(2+2)=8$

$a_{3}=3(3+2)=15$

$a_{4}=4(4+2)=24$

$a_{5}=5(5+2)=35$

Therefore, the required terms are $3,8,15,24$ and $35 .$

Standard 11
Mathematics

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