Write the first three terms in each of the following sequences defined by the following:

$a_{n}=\frac{n-3}{4}$

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Here $a_{n}=\frac{n-3}{4} .$ Thus, $a_{1}=\frac{1-3}{4}=-\frac{1}{2}, a_{2}=-\frac{1}{4}, a_{3}=0$

Hence, the first three terms are $-\frac{1}{2},-\frac{1}{4}$ and $0 .$

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