8. Sequences and Series
easy

दी गई परिभाषाओं के आधार पर निम्नलिखित प्रत्येक अनुक्रम के प्रथम तीन पद बताइए

$a_{n}=\frac{n-3}{4}$

A

$-\frac{1}{2},-\frac{1}{4},0$

B

$-\frac{1}{2},-\frac{1}{4},0$

C

$-\frac{1}{2},-\frac{1}{4},0$

D

$-\frac{1}{2},-\frac{1}{4},0$

Solution

Here $a_{n}=\frac{n-3}{4} .$ Thus, $a_{1}=\frac{1-3}{4}=-\frac{1}{2}, a_{2}=-\frac{1}{4}, a_{3}=0$

Hence, the first three terms are $-\frac{1}{2},-\frac{1}{4}$ and $0 .$

Standard 11
Mathematics

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