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8. Sequences and Series
easy
दी गई परिभाषाओं के आधार पर निम्नलिखित प्रत्येक अनुक्रम के प्रथम तीन पद बताइए
$a_{n}=\frac{n-3}{4}$
A
$-\frac{1}{2},-\frac{1}{4},0$
B
$-\frac{1}{2},-\frac{1}{4},0$
C
$-\frac{1}{2},-\frac{1}{4},0$
D
$-\frac{1}{2},-\frac{1}{4},0$
Solution
Here $a_{n}=\frac{n-3}{4} .$ Thus, $a_{1}=\frac{1-3}{4}=-\frac{1}{2}, a_{2}=-\frac{1}{4}, a_{3}=0$
Hence, the first three terms are $-\frac{1}{2},-\frac{1}{4}$ and $0 .$
Standard 11
Mathematics