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14.Probability
medium
A bag contains $9$ discs of which $4$ are red, $3$ are blue and $2$ are yellow. The discs are similar in shape and size. A disc is drawn at random from the bag. Calculate the probability that it will be either red or blue.
A
$\frac{7}{9}$
B
$\frac{7}{9}$
C
$\frac{7}{9}$
D
$\frac{7}{9}$
Solution
There are $9$ discs in all so the total number of possible outcomes is $9 .$
Let the events $A, \,B, \,C$ be defined as
$A:$ 'the disc drawn is red'
$B:$ 'the disc drawn is yellow'
$C:$ 'the disc drawn is blue'.
The event 'either red or blue' may be described by the set $'A$ or $C'$
since, $A$ and $C$ are mutually exclusive events, we have
$P ( A \text { or } C )= P ( A \cup C )$ $= P ( A )+ P ( C )=\frac{4}{9}+\frac{1}{3}=\frac{7}{9}$
Standard 11
Mathematics
