એક કોલેજ દ્વારા પુરુષોની રમતમાં 38 ચંદ્રકો ફૂ | vedclass

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Question

Let $F, B$ and $C$ denote the set of men who received medals in football, basketball and cricket. respectively.

Then $n( F )=38, n( B )=15, n( C )=

Vedclass · Accepted Answer

Vedclass · Answer

Let $F, B$ and $C$ denote the set of men who received medals in football, basketball and cricket. respectively.

Then $n( F )=38, n( B )=15, n( C )=20$

$n( F \cup B \cup C )=58$ and $n( F \cap B \cap C )=3$

Therefore, $\quad n( F \cup B \cup C )=n( F )+n( B )$

$+n( C )-n( F \cap B )-n( F \cap C )-n( B \cap C )+$

$n( F \cap B \cap C )$

gives $n( F \cap B )+n( F \cap C )+n( B \cap C )=18$

Consider the Venn diagram as given in Fig 

Here, $a$ denotes the number of men who got medals in football and basketball only, $b$ denotes the number of men who got medals in football and cricket only, $c$ denotes the number of men who got medals in basket ball and cricket only and $d$ denotes the number of men who got medal in all the three.

Thus, $d=n( F \cap B \cap C )=3$ and  $a+d+b+d+c+d=18$

Therefore $a+b+c=9,$

which is the number of people who got medals in exactly two of the three sports.

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