Find the equation of the ellipse, with major axis along the $x-$ axis and passing through the points $(4,\,3)$ and $(-1,\,4)$

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Solution The standard form of the ellipse is $\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1 .$

since the points $(4,\,3)$ and $(-1,\,4)$ lie on the ellipse, we have

$\frac{16}{a^{2}}+\frac{9}{b^{2}}=1$      ............ $(1)$

and      $\frac{1}{a^{2}}+\frac{16}{b^{2}}=1$  ......... $(2)$

Solving equations $(1)$ and $(2),$ we find that $a^{2}=\frac{247}{7}$ and $b^{2}=\frac{247}{15}$

Hence the required equation is

$\frac{x^{2}}{\left(\frac{247}{7}\right)}$ $+\frac{y^{2}}{\frac{247}{15}}=1,$ i.e., $7 x^{2}+15 y^{2}=247$

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