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14.Probability
medium
આપેલ ઘટનાઓ $A$ અને $B$ માટે $P(A)=\frac{1}{2}, P(A \cup B)=\frac{3}{5}$ અને $\mathrm{P}(\mathrm{B})=p .$ આપેલ છે. જો ઘટનાઓ પરસ્પર નિવારક $p$ માં શોધો.
A
$\frac {1}{10}$
B
$\frac {1}{10}$
C
$\frac {1}{10}$
D
$\frac {1}{10}$
Solution
It is given that $P(A)=\frac{1}{2},\, P(A \cup B)=\frac{3}{5}$ and $P(B)=p$
When $A$ and $B$ are mutually exclusive, $A \cap B=\phi$
$\therefore P(A \cap B)=0$
It is known that, $P(A \cup B)=P(A)+P(B)-P(A \cap B)$
$\Rightarrow \frac{3}{5}=\frac{1}{2}+p-0$
$\Rightarrow p=\frac{3}{5}-\frac{1}{2}=\frac{1}{10}$
Standard 11
Mathematics
