If $\tan \beta = \cos \theta \tan \alpha ,$ then ${\tan ^2}\frac{\theta }{2} = $
If $\tan \beta = \cos \theta \tan \alpha ,$ then ${\tan ^2}\frac{\theta }{2} = $
- A
$\frac{{\sin (\alpha + \beta )}}{{\sin (\alpha - \beta )}}$
- B
$\frac{{\cos (\alpha - \beta )}}{{\cos (\alpha + \beta )}}$
- C
$\frac{{\sin (\alpha - \beta )}}{{\sin (\alpha + \beta )}}$
- D
$\frac{{\cos (\alpha + \beta )}}{{\cos (\alpha - \beta )}}$
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