यदि $\tan \,(A + B) = p,\,\,\tan \,(A - B) = q,$ तो $\tan \,2A$ का मान $p$ तथा $q$ के पदों में है
$\frac{{p + q}}{{p - q}}$
$\frac{{p - q}}{{1 + pq}}$
$\frac{{p + q}}{{1 - pq}}$
$\frac{{1 + pq}}{{1 - p}}$
${(\cos \alpha + \cos \beta )^2} + {(\sin \alpha + \sin \beta )^2} = $
${\cos ^2}A{(3 - 4{\cos ^2}A)^2} + {\sin ^2}A{(3 - 4{\sin ^2}A)^2} = $
$\sqrt 2 + \sqrt 3 + \sqrt 4 + \sqrt 6 = $
$2\,{\sin ^2}\beta + 4\,\,\cos \,(\alpha + \beta )\,\,\sin \,\alpha \,\sin \,\beta + \cos \,2\,(\alpha + \beta ) = $
यदि $\tan x = \frac{b}{a},$ तो $\sqrt {\frac{{a + b}}{{a - b}}} + \sqrt {\frac{{a - b}}{{a + b}}} = $