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8. Sequences and Series
medium
यदि किसी समांतर श्रेणी के $n$ पदों का योग $n P +\frac{1}{2} n(n-1) Q$, है, जहाँ $P$ तथा $Q$ अचर हो तो सार्व अंतर ज्ञात कीजिए।
A
$Q$
B
$Q$
C
$Q$
D
$Q$
Solution
Let $a_{1}, a_{2}, \ldots a_{n}$ be the given $\mathrm{A.P.}$ Then
${S_n} = {a_1} + {a_2} + {a_3} + \ldots + {a_{n – 1}} + {a_n} = nP + \frac{1}{2}n(n – 1)Q$
Therefore $S_{1}=a_{1}=P, S_{2}=a_{1}+a_{2}=2 P+Q$
So that $a_{2}= S _{2}- S _{1}= P + Q$
Hence, the common difference is given by $d=a_{2}-a_{1}=(P+Q)-P=Q$
Standard 11
Mathematics
