Let $p, q$ and $r$ be real numbers $(p \ne q,r \ne 0),$ such that the roots of the equation $\frac{1}{{x + p}} + \frac{1}{{x + q}} = \frac{1}{r}$ are equal in magnitude but opposite in sign, then the sum of squares of these roots is equal to .
Let $p, q$ and $r$ be real numbers $(p \ne q,r \ne 0),$ such that the roots of the equation $\frac{1}{{x + p}} + \frac{1}{{x + q}} = \frac{1}{r}$ are equal in magnitude but opposite in sign, then the sum of squares of these roots is equal to .
- [JEE MAIN 2018]
- A
${p^2} + {q^2} + {r^2}$
- B
${p^2} + {q^2}$
- C
$2({p^2} + {q^2})$
- D
$\frac{{{p^2} + {q^2}}}{2}$
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