The inequality $|z - 4|\, < \,|\,z - 2|$represents the region given by

  • [AIEEE 2002]
  • [IIT 1982]
  • A

    ${\mathop{\rm Re}\nolimits} (z) > 0$

  • B

    ${\mathop{\rm Re}\nolimits} (z) < 0$

  • C

    ${\mathop{\rm Re}\nolimits} (z) > 2$

  • D

    None of these

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If ${z_1} = a + ib$ and ${z_2} = c + id$ are complex numbers such that $|{z_1}| = |{z_2}| = 1$ and $R({z_1}\overline {{z_2}} ) = 0,$ then the pair of complex numbers ${w_1} = a + ic$ and ${w_2} = b + id$ satisfies

  • [IIT 1985]

Let $z_1$ and $z_2$ be any two non-zero complex numbers such that $3\left| {{z_1}} \right| = 4\left| {{z_2}} \right|$. If $z = \frac{{3{z_1}}}{{2{z_2}}} + \frac{{2{z_2}}}{{3{z_1}}}$ then

  • [JEE MAIN 2019]

If $arg\,z < 0$ then $arg\,( - z) - arg\,(z)$ is equal to

  • [IIT 2000]

Let $z$ be complex number satisfying $|z|^3+2 z^2+4 z-8=0$, where $\bar{z}$ denotes the complex conjugate of $z$. Let the imaginary part of $z$ be nonzero.

Match each entry in List-$I$ to the correct entries in List-$II$.

List-$I$ List-$II$
($P$) $|z|^2$ is equal to ($1$) $12$
($Q$) $|z-\bar{z}|^2$ is equal to ($2$) $4$
($R$) $|z|^2+|z+\bar{z}|^2$ is equal to ($3$) $8$
($S$) $|z+1|^2$ is equal to ($4$) $10$
  ($5$) $7$

The correct option is:

  • [IIT 2023]