7.Binomial Theorem
hard

वह न्यूनतम प्राकृत संख्या $n$, जिसके लिए $\left( x ^{2}+\frac{1}{ x ^{3}}\right)^{ n }$ के प्रसार में $x$ का गुणांक ${ }^{ n } C _{23}$ है

A

$38$

B

$58$

C

$23$

D

$35$

(JEE MAIN-2019)

Solution

${T_{r + 1}}\, = \,\sum\limits_{r = 0}^n {^n{C_r}\,{x^{2n – 2r}}\,.\,{x^{ – 3r}}} $

$2n – 5r = 1\Rightarrow 2n = 5r + 1$ for $r = 15, n = 38$ smallest value of $n$ is $38$.

Standard 11
Mathematics

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