સમકેન્દ્રિય ગોળીય કવચ A અને B ની ત્રિજ | vedclass

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Question

(a) Inside the shell $A$, electric field $E_{in} = 0$
At the surface of shell $A$,
${E_A} = \frac{{k\,{Q_A}}}{{r_A^2}}$ $\xrightarrow{\,}$ (a fixed

Vedclass · Accepted Answer

Vedclass · Answer

(a) Inside the shell $A$, electric field $E_{in} = 0$
At the surface of shell $A$,
${E_A} = \frac{{k\,{Q_A}}}{{r_A^2}}$ $\xrightarrow{\,}$ (a fixed positive value)
Between the shell $A$ and $B$, at a distance $x$ from the common centre
$E = \frac{{k.\,{Q_A}}}{{{x^2}}}$ $\xrightarrow{\,}$  (as $x$ increases $E$ decreases)
At the surface of shell $B$,
${E_B} = \frac{{k.\,({Q_A} - {Q_B})}}{{r_B^2}}$ $\xrightarrow{\,}$ (a fixed negative value because $|QA| < |QB|)$
Outside the both shell, at a distance $x$ from the common centre
${E_{out}} = \frac{{k({Q_A} - {Q_B})}}{{x{'^2}}}$ $\xrightarrow{\,}$  (as $x$ increases negative value of Eout decreases and it becomes zero at $x = \infty$)

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