8. Sequences and Series
easy

પ્રથમ ત્રણ પદો લખો : $a_{n}=2 n+5$

A

$7,9,11$

B

$7,9,11$

C

$7,9,11$

D

$7,9,11$

Solution

Here $a_{n}=2 n+5$

Substituting $ n =1,2,3, $ we get 

$a_{1} =2(1)+5=7, a_{2}=9, a_{3}=11$

Therefore, the required terms are $7,9$ and $11 .$

Standard 11
Mathematics

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